Question

tolong di jawab jangan ngasal​

Answer 1

Jawab:

Penjelasan dengan langkah-langkah:

nomor 1

f'(x) < 0

3x^2 - 18x - 48 < 0

3(x^2 - 6x - 16) < 0

3(x + 2)(x - 8) < 0

-2 < x < 8

nomor 2

f'(x) > 0

3x^2 + 6x - 9 > 0

3(x^2 + 2x - 3) > 0

3(x + 3)(x - 1) > 0

x < -3 atau x > 1

nomor 3

f'(x) = 0

6x^2 - 18x + 12 = 0

6(x^2 - 3x + 2) = 0

6(x - 2)(x - 1) = 0

x = 2

x = 1

f''(x) = 12x - 18

f''(2) = 12(2) - 18 = 6 (titik minimum)

f''(1) = 12(1) - 18 = -6 (titik maksimum)

f(1) = 2 - 9 + 12 = -7 + 12 = 5

titik maksimum = (1,5)