Jawaban:
a. V kerucut = 1/3 × π × r × r × t
= 1/3 × 22/7 × (14:2) × (14:2) × 12
= 1/3 × 22/7 × 7 × 7 × 12
= 616 cm³
V tabung = π × r × r × t
= 22/7 × 7 × 7 × 16
= 2.464 cm³
V gabungan = V kerucut + V tabung
= 616 + 2.464
= 3.080 cm³
1. L permukaan balok = 2 × (pl + lt + pt)
= 2 × ( (10 × 3) + (3 × 4) + (10 × 4)
= 2 × ( 30 + 12 + 40)
= 2 × 82
= 164 cm²
2. L permukaan kubus = 6 × s²
= 6 × 23²
= 6 × 529
= 3.174 cm²
3. L permukaan tabung = 2 × π r (r + t)
= 2 × 22/7 × 14 × (14 + 20)
= 2 × 22 × 7 × 34
= 10.472²
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Jawaban:
a. V kerucut = 1/3 × π × r × r × t
= 1/3 × 22/7 × (14:2) × (14:2) × 12
= 1/3 × 22/7 × 7 × 7 × 12
= 616 cm³
V tabung = π × r × r × t
= 22/7 × 7 × 7 × 16
= 2.464 cm³
V gabungan = V kerucut + V tabung
= 616 + 2.464
= 3.080 cm³
1. L permukaan balok = 2 × (pl + lt + pt)
= 2 × ( (10 × 3) + (3 × 4) + (10 × 4)
= 2 × ( 30 + 12 + 40)
= 2 × 82
= 164 cm²
2. L permukaan kubus = 6 × s²
= 6 × 23²
= 6 × 529
= 3.174 cm²
3. L permukaan tabung = 2 × π r (r + t)
= 2 × 22/7 × 14 × (14 + 20)
= 2 × 22 × 7 × 34
= 10.472²
#semoga membantu