Tolong di Jawab dan kasih step by step! Gw kasih 100 point.... Question from @evareagan79

DB45

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Penjelasan dengan langkah-langkah:

bentuk sederhana

$\sf a). \dfrac{2x^2 + x - 1}{2x^2 + 5x - 3}=$

$\sf =\dfrac{(2x-1)(x + 1)}{(2x- 1)(x + 3)}$

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$\sf = \dfrac{(a-5)(a+7)}{(a + 7)(a + 7)}$

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$\sf = \dfrac{(3x-2)(2x - 3)}{(3x - 2)(x+4)}$

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$\sf =\dfrac{(2t+5)(t-3)(t - 3)(t+2)}{(t+2)(t -3)(t-3)}$

$\sf = 2t+5$

2 votes Thanks 3

DETECTlVE

Bagian A

$\boxed{\begin{aligned}\sf \frac{ {2x}^{2} + x - 1}{ {2x}^{2} + 5x - 3} &=\sf \frac{2x(x + 1) - (x + 1)}{2x(x + 3) - (x + 3)} \\\sf &=\sf \frac{(x + 1)( \cancel{2x - 1})}{(x + 3)( \cancel{2x - 1})} \\ \sf &= \sf \frac{x + 1}{x + 3 } \end{aligned}}$

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Bagian B

$\boxed{\begin{aligned}\sf \frac{ {a}^{2} + 2a - 35 }{ {a}^{2} + 14a + 49} &=\sf \frac{a(a + 7) - 5(a + 7)}{(a + 7)(a + 7)} \\ \sf &=\sf \frac{( \cancel{a + 7})(a - 5)}{( \cancel{a + 7})(a + 7)} \\ \sf &= \sf \frac{a - 5}{a + 7}\end{aligned}}$

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Bagian C

$\boxed{\begin{aligned}\sf \frac{ {6x}^{2} - 13x + 6 }{ {3x}^{2} + 10x - 8 } &=\sf \frac{2x(3x - 2) - 3(3x - 2)}{3x(x + 4) - 2(x + 4)} \\ \sf &=\sf \frac{(\cancel{3x - 2})(2x - 3)}{(x + 4)( \cancel{3x - 2})} \\ \sf &= \sf \frac{2x - 3}{x + 4} \end{aligned}}$