Question

Tolong di bantu ya.
Tentukan nilai x yang memenuhi persamaan berikut!!
A . Log(6x + 8) = log(2x - 4) + log8
B . Log2x - log4 = log32

Answer 1

A) log (6x + 8) = log (2x - 4) + log 8
    log (6x + 8) = log [(2x - 4). 8]
    log (6x + 8) = log (16x - 32)
    6x + 8 = 16x - 32
    10x = 40
     x = 4
b)
log 2x - log 4 = log 32
log (2x/4) = log 32
log x/2 = log 32
x/2 = 32
x = 64