Tolong di bantu ya, saya kurang ngerti.... Question from @ismiazizah371

October 2018 2 124 Report

Tolong di bantu ya, saya kurang ngerti

royardika Lim tan(3x-π)cos2x/sin (3x-π)
= lim sin (3x-π)cos2x/cos (3x-π)sin (3x-π)
= lim cos2x/cos (3x-π)
= cos 2( π/3)/cos(3( π/3)- π)
= cos 120/cos 0
= -1/2

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ismiazizah371 maksih ya

izharulhaq78 $\lim_{x\to\frac{\pi}{3}}\frac{\tan(3x-\pi)\cos2x}{\sin(3x-\pi)}\\\lim_{x\to\frac{\pi}{3}}\frac{\frac{\sin(3x-\pi)}{\cos(3x-\pi)}\cos2x}{\sin(3x-\pi)}\\\lim_{x\to\frac{\pi}{3}}\frac{\sin(3x-\pi)\cos2x}{\sin(3x-\pi)\cos(3x-\pi)}\\\lim_{x\to\frac{\pi}{3}}\frac{\cos2x}{\cos(3x-\pi)}\\\frac{\cos2(\frac{\pi}{3})}{\cos(3(\frac{\pi}{3})-\pi)}\\\frac{\cos\frac{2\pi}{3}}{\cos(\pi-\pi)}\\\frac{\cos\frac{2\pi}{3}}{\cos0}\\\frac{-\frac{1}{2}}{1}\\-\frac{1}{2}$

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