[tex]volume \: balok + \frac{1}{2} \: tabung \\ \\ p \times l(t + \frac{l}{8} \pi) \\ \\ 20 \times 14(10 + \frac{14}{8} \times \frac{22}{7} ) \\ \\ 280(10 + 5,5) \\ \\ 280(15,5) \\ \\ 4.340 \: {cm}^{3} [/tex]
Jawaban:
Volume balok :
V = p × l × t
V = 20 × 14 × 10
V = 20 × 140
V = 2.800 cm³
.
Volume ½ tabung
V = ½ × (π × r² × t)
V = ½ × (22/7 × 7² × 20)
V = ½ × (22/7 × 49 × 20)
V = ½ × (22 × 7 × 20)
V = ½ × 3.080
V = 1.540 cm³
Volume gabungan balok & Volume ½ tabung
Volume gabungan = Vbalok + V½tabung
Volume gabungan = 2.800 + 1.540 cm³
Volume gabungan = 4.340 cm³
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Verified answer
[tex]volume \: balok + \frac{1}{2} \: tabung \\ \\ p \times l(t + \frac{l}{8} \pi) \\ \\ 20 \times 14(10 + \frac{14}{8} \times \frac{22}{7} ) \\ \\ 280(10 + 5,5) \\ \\ 280(15,5) \\ \\ 4.340 \: {cm}^{3} [/tex]
Jawaban:
Penyelesaian :
Volume gabungan
Volume balok :
V = p × l × t
V = 20 × 14 × 10
V = 20 × 140
V = 2.800 cm³
.
Volume ½ tabung
V = ½ × (π × r² × t)
V = ½ × (22/7 × 7² × 20)
V = ½ × (22/7 × 49 × 20)
V = ½ × (22 × 7 × 20)
V = ½ × 3.080
V = 1.540 cm³
.
Volume gabungan balok & Volume ½ tabung
Volume gabungan = Vbalok + V½tabung
Volume gabungan = 2.800 + 1.540 cm³
Volume gabungan = 4.340 cm³