Penjelasan:
I = 0,5 A
V = 6 Volt
r = 1 Ω
Hambatan total lampu :
R = x Ω + 1 Ω
R = (x + 1) Ω
Besar hambatan lampu x :
V = I . R
6 = 0,5 . (x + 1)
12 = x + 1
x = 11 Ω
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Penjelasan:
I = 0,5 A
V = 6 Volt
r = 1 Ω
Hambatan total lampu :
R = x Ω + 1 Ω
R = (x + 1) Ω
Besar hambatan lampu x :
V = I . R
6 = 0,5 . (x + 1)
12 = x + 1
x = 11 Ω