Question

Tolong di bantu ya. Ini tentang kapasitor

Answer 1

1a. Kapasitas pengganti C=CA + CB +CC

C= 10+20+30 = 60 μC

b. VA = qA.CA = 1,2.10⁻⁹ .60.10⁻⁶ = 0,72 volt

Karena kapasitor paralel maka VB =VC = VA = 0,,72 volt

c. qB = CB . VB = 20.10⁻⁶.0,72 = 14,4.10⁻⁶ 14,4 μF = 0,144 nF

qC = CC . VC = 30.10⁻⁶.0,72 = 21,6.10⁻⁶ 14,4 μF = 0,216 nF

2a. Paralel Cp = C1 + C2 = 10 + 20 = 30 μF

Seri 1/Cs = 1/Cp + 1/C3 = 1/30 +1/30 = 2/30

Cs = 30/2 =15 μF

2b. C1 dan C2 tegangannya sama V12

E = V12 + V3= q/Cp + q/C3

30 = q( 1/ 30.10⁻⁶ + 1/ 30.10⁻⁶)

q = 30 ( 30.10⁻⁶ ) / 2

q = 450.10⁻⁶ C

q3 = q = 450.10⁻⁶ C

V3 = q3/C3 = 450.10⁻⁶/30.10⁻⁶= 15 V

Krn paralel V1 + V2 = E - V3 = 30 - 15 = 15 V

q1 = C1.V1 = 10.10⁻⁶ x 15 = 150.10⁻⁶ C

q2 = C2.V2 = 20.10⁻⁶ x 15 = 300.10⁻⁶ C

2c. Titik A dan B tidak ada digambar