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Verified answer
Bab TrigonometriMatematika SMA Kelas X
BD = 2 . BC
tan x = AB/BC
AB = BC . tan x
tan D = AB / BD
tan D = AB / (2 BC)
tan D = (BC . tan x) / (2 . BC)
tan D = ( tan x )/2 → y/x
r = √(x² + y²)
r = √(2² + (tan x)²)
r = √(4 + tan² x)
cos D = x/r
cos D = 2/(√(4 + tan² x))
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