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3x + y≥30 (0,30)(10,0)
x + 2y ≥ 40 (0,20)(40,0)
3x + y = 30 | .2
x + 2y = 40 | .1
6x + 2y = 60
x + 2y = 40
__________ -
5x = 20
x = 4
x+2y = 40
2y = 40 - 4
y = 18 (4,18)
Karena yg ditanya maksimum,
maka titik2nya adalah
(0,20) = 20
(10,0) = 10
(4,18) = 22
Jadi banyak pakaian maks yg dapat dibuat adalah 22 .Semoga membantu