" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
karena akar kembar maka D=0
b^2-4ac = 0
a^2-4.1.(a-1)= 0
a^2-(4a-4) = 0
a^2-4a+4 = 0
(a -2)(a-2)
a-2 =0
a = 2
a = 1, b = a, c = (a - 1)
Karena akar-akrnya kembar, maka D = 0
D = 0
⇒ b² - 4ac = 0
⇒ a² - 4(1)(a - 1) = 0
⇒ a² - 4a + 4 = 0
⇒ (a - 2)² = 0
⇒ a - 2 = 0
⇒ a = 2
Jadi, nilai a = 2
Terimakaish semoga membantu