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2.p=2,q=6,r=4,s=6
3. 2 C6H6 + 7 O2 ---->4 CO2 + 6 H2O
40 L
koef C6H6 / koef CO2 × volume C6H6
= 2/4×40
=20 Liter
4. n=m/Mr
= 1,2 × 60
= 72 mol
5. V= n × Vm (Vm=22,4)
n=V/Vm
= 5,6/22,4
= 0,25 mol
6. N2O3
7. 6.4 gram
semoga membantu :)
jangan lupa bintang 5 nya mas