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maka mol kristal= 246/.(120+18x)
mol Mg(OH)2 = 120/120 = 1 mol
mol H20 = x/1 . 1 mol = x mol
246/(120+18x ) = 1 + x
246 = 120 + 120x + 18x + 18x^2
126 = 128x + 18x^2
lanjutkan ya...
#tinggal faktorkan
massa H2O = 246 - 120 = 126 gram
mol MgSO4 : mol H2O = 120/120 : 126/18 = 1 : 7
jadi rumus molekulnya MgSO4.7H2O