" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2q - p = 5 ......(2)
5p + r = 3 ......(3)
q + r = 1
q = 1 - r atau r = 1 - q
substitusi ke persamaan 2
2q - p = 5
2 (1 - r ) - p = 5
2 - 2r - p = 5
-2r - p = 3
eliminasi -2r - p = 3 dengan persamaan 3
5p + r = 3 × 1
-p - 2r = 3 ×5
menjadi:
5p + r = 3
-5p -10r = 15
-------------------- +
-9r = 18
r = -(18/9) = -2
substitusi r = -2 ke pers 1 dan persamaan 3
q + r = 1 persamaan (1)
q + (-2) = 1
q - 2 = 1
q = 3
5p + r = 3
5p + (-2) = 3
5p - 2 = 3
5p = 5
p = 5/5
p = 1
jadi nilai p = 1, q = 3 dan r = -2