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Kelas 11 MatematikaBab Program Linear
4 . 4 = 16
3 . 4 = 12
Tipe I = x
Tipe II = y
16x + 12y <= 960 → dibagi 4 → 4x + 3y <= 240
x + y <= 70
x = -y + 70
4x + 3y = 240
4 (-y + 70) + 3u = 240
-4y + 280 + 3y = 240
-y = 240 - 280
y = 40
x = -y + 70
x = -40 + 70
x = 30
(30, 40)
x + y = 70
(0, 70) dan (70, 0)
4x + 3y = 240
(0, 80) dan (60, 0)
f(x, y) = 4.000.000x + 3.500.000y
f(0, 80) = 0 + 3.500.000 . 80
f(0, 80) = Rp 280.000.000,00
f(70, 0) = 4.000.000 . 70 + 0
f(70, 0) = Rp 280.000.000,00
f(30, 40) = 4.000.000 . 30 + 3.500.000 . 40
f(30, 40) = 120.000.000 + 140.000.000
f(30, 40) = Rp 260.000.000,00
Keuntungan maksimum = Rp 280.000.000,00 jika ada kamar tipe I atau II yang boleh kosong
Keuntungan maksimum = Rp 260.000.000,00 jika ada kamar tipe I atau II tidak boleh kosong