Materi : Kesebangunan dan Kekonggruenan
CD² = √[ 15² - 9² ] = √144 = 12 cm
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∆ACD sebangun ∆ABC
∆ACD ( a¹ = 12 , t¹ = 9 , s¹ = 15 )
∆ABC ( a² = BC , t² = 15 , s² = AB )
a²/a¹ = t²/t¹
a²/12 = 15/9
a² = 12 . 5/3
a² = 4 . 5
a² = 20 cm
L = ½ . AC . BC
L = ½ . 15 cm . 20 cm
L = 15 cm . 10 cm
L = 150 cm² { pilihan 3 }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Verified answer
Materi : Kesebangunan dan Kekonggruenan
CD² = √[ 15² - 9² ] = √144 = 12 cm
__________________________/
∆ACD sebangun ∆ABC
∆ACD ( a¹ = 12 , t¹ = 9 , s¹ = 15 )
∆ABC ( a² = BC , t² = 15 , s² = AB )
Cari Alas ( a² = BC )
a²/a¹ = t²/t¹
a²/12 = 15/9
a² = 12 . 5/3
a² = 4 . 5
a² = 20 cm
Langsung Saja
L = ½ . AC . BC
L = ½ . 15 cm . 20 cm
L = 15 cm . 10 cm
L = 150 cm² { pilihan 3 }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]