Question

Tolong bantuin yaa....
1) Limit (4x per x²-4 dikurangi 2 per x-2) x mendekati 2

2) Limit x²-4 per x³-8 dengan x mendekati 2

makasih :)

Answer 1

1) lim (4x / (x² - 4) - 2/(x - 2))
  x->2
= lim (4x(x - 2) - 2(x² - 4)) / (x - 2)(x² - 4)
 x-> 2
= lim (2x² - 8x + 8) / (x - 2)(x² - 4)
 x-> 2
= lim (2(x - 2)²)/(x - 2)²(x + 2)
x-> 2
= lim 2/(x + 2)
x-> 2
= 2/4
= 1/2

2) lim (x² - 4)/(x³ - 8)
x-> 2
pakai hopital
lim (2x)/(3x²)
x-> 2
= lim 2/3x
x-> 2
= 1/3

Answer 2

1)







2)