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BC = 20
Catatan sifat segitiga siku-siku sisinya 3 4 5 atau kelipatannya
BC = 20 CD = 25
Maka BD = 15
x =
x = 15
Panjang DC = 25
Maka :
DC² = BC² + BD²
25² = 20² + BD²
BD² = 25² - 20²
BD² = 625 - 400
BD² = 225
BD =
BD = 15 cm
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