Jawaban:
emang Kaka kelas berapa
Penjelasan dengan langkah-langkah:
operasi hitung/eksponen
[tex] {a}^{m} \times {a}^{n} = {a}^{m + n} \\ \sqrt[3]{ {a}^{3} } = a \\ ( {a}^{m} ) {}^{n} = {a}^{mn} [/tex]
berlaku:
[tex] {27}^{3} \div {3}^{3} + {5}^{3} \times \sqrt[3]{1728} - \sqrt[3]{24389} \\ ( {3}^{3} ) {}^{3} \div {3}^{3} + (5 \times 5 \times 5) \times \sqrt[3]{ {12}^{3} } - \sqrt[3]{ {29}^{3} } \\ {3}^{9} \div {3}^{3} + 125 \times 12 - 29 \\ {3}^{9 - 3} + (125 \times 12) - 29 \\ {3}^{6} + 1500 - 29 \\ 729 + 1500 - 29 = 2229 - 29 = 2200[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawaban:
emang Kaka kelas berapa
Verified answer
Penjelasan dengan langkah-langkah:
operasi hitung/eksponen
[tex] {a}^{m} \times {a}^{n} = {a}^{m + n} \\ \sqrt[3]{ {a}^{3} } = a \\ ( {a}^{m} ) {}^{n} = {a}^{mn} [/tex]
berlaku:
[tex] {27}^{3} \div {3}^{3} + {5}^{3} \times \sqrt[3]{1728} - \sqrt[3]{24389} \\ ( {3}^{3} ) {}^{3} \div {3}^{3} + (5 \times 5 \times 5) \times \sqrt[3]{ {12}^{3} } - \sqrt[3]{ {29}^{3} } \\ {3}^{9} \div {3}^{3} + 125 \times 12 - 29 \\ {3}^{9 - 3} + (125 \times 12) - 29 \\ {3}^{6} + 1500 - 29 \\ 729 + 1500 - 29 = 2229 - 29 = 2200[/tex]