Penjelasan dengan langkah-langkah:
1.
zA + zB = 90°
3x - 10 + x + 16 = 90°
4x = 90-6
x = 84/4 = 21°
..... zA = 3(21)-10 = 53°
2.
3x - 42 = 2x + 7
3x - 2x = 42 + 7
x = 49°
y + 42 = 3x - 42
y = 3(49) - 2(42)
y = 147 - 84
y = 63°
x + y = 49 + 63 = 112°
4.
sudut dalam berseberangan
= P2 dan Q4, P3 dan Q1
5. x = 38°
y = (180-38)/2
y = 142/2
y = 71°
z = x + y
z = 38 + 71
z = 109°
6.
3x - 10 + x + 8 = 180
4x = 182
x = 182/4
x = 91/2
x = 45,5°
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Penjelasan dengan langkah-langkah:
1.
zA + zB = 90°
3x - 10 + x + 16 = 90°
4x = 90-6
x = 84/4 = 21°
..... zA = 3(21)-10 = 53°
2.
3x - 42 = 2x + 7
3x - 2x = 42 + 7
x = 49°
y + 42 = 3x - 42
y = 3(49) - 2(42)
y = 147 - 84
y = 63°
x + y = 49 + 63 = 112°
4.
sudut dalam berseberangan
= P2 dan Q4, P3 dan Q1
5. x = 38°
y = (180-38)/2
y = 142/2
y = 71°
z = x + y
z = 38 + 71
z = 109°
6.
3x - 10 + x + 8 = 180
4x = 182
x = 182/4
x = 91/2
x = 45,5°