Question

tolong bantuin jawab pr saya kak​

Answer 1

Verified answer

Materi : Bentuk dan Persamaan Kuadrat

Bentuk umum : ax² + bx + c = 0

x² - 7x + 12 = 0 { a = 1, b = -7, c = 12 }

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A. x¹ + x² = -b/a = -(-7)/1 = 7/1 = 7

B. x¹ . x² = c/a = 12/1 = 12

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C. 1/x¹ + 1/x²

= x²/( x¹ . x² ) + x¹/( x¹ . x² )

= ( x¹ + x² )/( x¹ . x² )

= 7/12

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D. (x¹)² + (x²)²

= ( x¹ + x² )² - 2x¹.x²

= 7² - 2(12)

= 49 - 24

= 25

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E. x¹(x²)² + x²(x¹)²

= x¹ . x² . x² + x¹ . x¹ . x²

= ( x¹ . x² )( x¹ + x² )

= 12 . 7

= 84

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Answer 2

1. x^2 - 7x + 12 = 0

a = 1 | b = -7 | c = 12

a. x1 + x2

= -b/a

= - -7/1

= 7/1

= 7

b. x1.x2

= c/a

= 12/1

= 12

c. 1/x1 + 1/x2

= x1 + x2/x1.x2

= 7/12

d. x1^2 + x2^2

= (x1 + x2)^2 - 2x1.x2

= (7)^2 - 2.12

= 49 - 24

= 25

e. x.x2^2 + x1^2.x2

= x1.x2(x1 + x2)

= 7(12)

= 7.12

= 84