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Verified answer
S + O2 -> SO2 HD= -296,8SO2 + 1/2 O2 -> SO3 HD = -98,9
S + 3/2 O2 -> SO3 HD = -395,7
Pelajaran : Kimia
Materi : Termokimia
Kelas : XI IPA
Pembahasan:
Dik:
S + O2 →→ SO2 ∆H= -296,8 Kj
2SO2 + O2 →→ 2SO3 ∆H= -197,8
maka:
- reaksi 1 (Dibalik) dan reaksi 2 (Dibalik)
SO2 →→ S + O2 ∆H= -296,8 Kj
SO3 →→ SO2 + 1/2 O2 = +197,8 /2 → 98,9
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jadi entalpi reaksi dari S + O2 → SO3 ∆H= -197,9 Kj
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