Question

Tolong bantuin besok dikumpulin

Answer 1

Panjang benda 20cm
s = 60cm
s1 = 80cm
p= 2,5d
f = 100/2,5
f = 40cm

ditanya ppanjang bayangan s' - s1' ??

cari untuk s' dulu

1/f = 1/s + 1/s'
1/40 = 1/60 + 1/s'
1/s' = 1/40 - 1/60
1/s' = 1/120
s' = 120cm

untuk s1'

1/f = 1/s1' + 1/s1
1/40 = 1/s1' + 1/80
1/s1' = 1/40 - 1/80
1/s1' = 1/80
s1' = 80cm

s' - s1' = 120 - 80 = 40cm(d.)

30.
R = 40cm
R = 2f
f = 20cm
s = 15cm

1/f = 1/s+1/s'
1/20 = 1/15 + 1/s'
1/s' = 1/20-1/15
1/s' = -1/60
s' = -60cm  -> tanda - menytakan benda maya dan tegak

M = s' / s
M = 60 / 15
M = 4 kali -> diperbesar

Jawaban maya tegak diperbesar(b)