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6. dik = <ABC = 2x' - 13'
<BCA = 5x' - 7'
<CAB = x'
dit = <BCA ?
jwb = 2x' - 13' + 5x' - 7' + x' = 180'
2x' + 5x' + x' = 180' + 13' + 7'
8x' = 200'
x = 200'
8'
x = 25'
\
jadi, <BCA = 5x' - 7'
= 5(25)' - 7'
= 125' - 7'
= 118' (a)