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Verified answer
Fungsi KomposisiKelas XI
f(x) = 1 - 2x
(g o f)(x) = 4x² - 6x + 3
g(f(x)) = 4x² - 6x + 3
g(1 - 2x) = 4x² - 6x + 3
Misal a = 1 - 2x
Maka x = (1 - a) / 2
g(a) = 4( [1 - a] / 2)² - 6( [1 - a] / 2) + 3
g(a) = 4 ( [1 - a]² / 4 ) - 3(1 - a) + 3
g(a) = 1 - 2a + a² - 3 + 3a + 3
g(a) = a² + a + 1
g(x) = x² + x + 1
___________________________
g(4) = 4² + 4 + 1
g(4) = 21
(f o g)(4) = f(g(4))
= f(21)
= 1 - 2(21)
= 1 - 42
= -41