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3y+5 = y+23
3y - y = 23 - 5
2y = 18
y = 9
besar sudut A:
3y + 5
= 3(9) + 5
= 27 + 5
= 32 (C)
no. 8
segitiga ABC = 180°
sudut BCA = sudut ABC
180° = sudut ABC + sudut 2BCA
180° = 56° + 2BCA
2BCA = 180° - 56°
2BCA = 124°
BCA = 62°