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n Na2SO4 = 7,1/142 = 0,05 mol
n H2O = 4,5/18 = 0,25 mol
koef Na2SO4/n Na2SO4 = koef H2O/n H2O
1/0,05 = x/0,25
x = 5 (jawaban e)
14. a sama dengan 125 gram (massa sebelum dan sesudah reaksi tetap)
15. n = PV/RT = (2 x 0,25)/(0,082 x 298) = 0,020462 mol
Mr = massa/n = 0,348/0,020462 = 17,0075 gram/mol
mendekati NH3