Tolong bantuannya kak, yang 5 b
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yuzar98
@
![\left[\begin{array}{ccc}5&5&5\\2&x&-1\\4&x^2&1\end{array}\right]\ = 0\\ 5 (x(1) -x^2(-1)) - 5(2(1) -4(-1) + 5 (2(x^2) -4(x)) = 0 \\ 5(x +x^2 ) - 5(2+4) + 5(2x^2 -4x) = 0\\ 5x + 5x^2 - 30 + 10x^2 -20x = 0 \\ 15x^2 - 15x - 30 = 0 \\ x^2 - x - 2 = 0 \\ (x + 1)(x - 2) = 0\\ x = -1 \\ x = 2](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%265%265%5C%5C2%26x%26-1%5C%5C4%26x%5E2%261%5Cend%7Barray%7D%5Cright%5D%5C+%3D+0%5C%5C%0A+5+%28x%281%29+-x%5E2%28-1%29%29++-+5%282%281%29++-4%28-1%29+%2B+5+%282%28x%5E2%29+-4%28x%29%29+%3D+0+%5C%5C%0A5%28x+%2Bx%5E2+%29+-+5%282%2B4%29+%2B+5%282x%5E2+-4x%29+%3D+0%5C%5C%0A5x+%2B+5x%5E2+-+30+%2B+10x%5E2+-20x++%3D+0+%5C%5C%0A15x%5E2+-+15x+-+30+%3D+0+%5C%5C%0Ax%5E2+-+x+-+2+%3D+0+%5C%5C%0A%28x+%2B+1%29%28x++-+2%29+%3D+0%5C%5C%0Ax+%3D+-1++%5C%5C%0Ax+%3D+2++ "\left[\begin{array}{ccc}5&5&5\\2&x&-1\\4&x^2&1\end{array}\right]\ = 0\\ 5 (x(1) -x^2(-1)) - 5(2(1) -4(-1) + 5 (2(x^2) -4(x)) = 0 \\ 5(x +x^2 ) - 5(2+4) + 5(2x^2 -4x) = 0\\ 5x + 5x^2 - 30 + 10x^2 -20x = 0 \\ 15x^2 - 15x - 30 = 0 \\ x^2 - x - 2 = 0 \\ (x + 1)(x - 2) = 0\\ x = -1 \\ x = 2")
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HilalAH
"menggunakan sifat sifat determinan" kak
HilalAH
yang sifat sperti "jika ada dua baris atau kolom yang sama maka determinannya = 0" ituloh kak, apakah dengan cara kofaktor itu juga termasuk sifatnya?
azaliavania21
Menurut saya ini jawabannya
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