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Verified answer
Rₚ₁ utk Hambatan 3 Ω dan 6 Ω :1/Rₚ₁ = 1/3 + 1/6
1/Rₚ₁ = 3/6
Rₚ₁ = 2 Ω
Rₛ utk Rₚ₁ dan hambatan 10 Ω
Rₛ = Rₚ₁ + 10
Rₛ = 2 + 10
Rₛ = 12 Ω
Rₚ₂ utk Rₛ dan Hambatan 12 Ω
Rₚ₂ = R / n (karena nilai R keduanya sama)
Rₚ₂ = 12 / 2
Rₚ₂ = 6 Ω
Maka
Rₜₒₜₐₗ = 6 + 6
Rₜₒₜₐₗ = 12 Ω