Question

Tolong bantu yang digambar ya.

Answer 1

Misalkan √3 = a dan √2 =b
maka
3x-2y=
3(a-b) / (a+b) - 2(a+b) / (a-b) =
[3(a-b)(a-b) - 2(a+b)(a+b)] / [(a+b)(a-b)] =
[3(a²-2ab+b²) - 2(a²+2ab+b²)] / (a²-b²) =
[3a²-6ab+3b² -2a²-4ab-2b²] / (a²-b²) =
[a²-10ab+b²] / (a²-b²)

substitusi a dan b
[√3² - 10(√3)(√2) + √2²] / (√3²-√2²) =
[3 - 10√6 + 2] / 1 =
5-10√6 = 5(1-2√6)