Question

Tolong bantu yaaaaaaaa pliiis
jika ka = CH3COOH = 10^-5 maka pH larutan CH3COONa 0,9 M = ???

Answer 1

Asam lemah memakai rumus
[H+] = √Ka x m
= √10^-5 x 9.10^-1
= √9.10^-6
= 3 x 10^-3

pH = - log 3.10^-3
= 3 - log 3
= 3 - 0,478
= 2, 522