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a=5t i + 4t j
v=(5/2.t^2 + c1) i + (4/2.t^2 + c2) j
v(0) = (5/2.0^2 +c1) i + (2. 0^2 + c2) j
v(0) = (c1) i + (c2) j
diketahui v0 = 2i - 2j
jadi c1=2 dan c2=-2
maka v(t)=(5/2.t^2 + 2) i + (2.t^2 - 2) j
v(10)=(5/2.(10^2) + 2) i + (2.(10^2) - 2) j
v(10)=(5/2.(100) + 2) i + (2.(100) - 2) j
v(10)=(...................) i + (................) j
itung sendiri