Question

Tolong bantu ya, sama tolong kasih penjelasannya terima kasih:)

Answer 1

4x-5y+10=0
m1= 4/5

syarat tegak lurus
m1.m2 = -1
4/5. m2=-1
m2= -5/4

melalui titik (2,-3) dgn m =-5/4
y-y1= m (x-x1)
y- (-3) = -5/4(x-2)
y+3 = -5/4x + 5/2. dikali 4
4y + 12 = -5x + 10
5x + 4y + 12-10 =0
5x+4y + 2 = 0
(B)