Question

Tolong bantu ya no 4 dan 5 pakai cara

Answer 1

4.
f(x) = 1/(5x -10)
g(x) = √(3x+2)

a) f+g (x) = 1/(5x -10)  + √(3x+2)
daerah asal
5x - 10 ≠ 0 atau 3x+2 > 0
x ≠ 2 atay x > - 2/3
daerah asal  - 2/3 < x < 2  atau x > 2

b)
P = 4. f(x²) - { g(x)}² 
P = 4. {1/ (5x² -10)} - {√(3x+2)}²
P = 4/(5x² -10) - (3x +2)
untuk x = -2 
P = 4/(5(4)-10)) - {3(-2) + 2}
P = 4/(20-10) - (6+2)
P = 4/10 - 8
P = - 76/10= - 7 ³/₅

5.
f(x) =  1/(x² - 36)
g(x) = 2x +12

f.g (x) = (2x +12)/(x² -36) = 2(x+6)/(x+6)(x-6)
f.g(x) = 2/(x-6)

daerah asal x - 6 ≠ 0
x ≠ 6