Question

Tolong bantu ya kakak.. yang B aja kakak

Answer 1

A) (0 int 5) f(x) dx = (0 int 2) (x + 2) dx + (2 int 5) (6 - x) dx
= (1/2 x^2 + 2x) (batas 0 s.d 2) + (6x - 1/2 x^2) (batas 2 s.d 5)
= (1/2 . 2^2 + 2.2) - (1/2 . 0^2 + 2.0) + (6.5 - 1/2 . 5^2) - (6.2 - 1/2 . 2^2)
= (6) - (0) + (30 - 25/2) - (10)
= 26 - 25/2
= 27/2
= 13 1/2

B) (0 int 5) f(x) dx = (0 int 1) (x) dx + (1 int 3) (1) dx + (3 int 5) (x - 4) dx
= (1/2 x^2) (bts 0 s.d 1) + (x) (bts 1 s.d 3) + (1/2 x^2 - 4x) (bts 3 s.d 5)
= (1/2 . 1^2) - (1/2. 0^2) + (3) - (1) + (1/2.5^2 - 4.5) - (1/2.3^2 - 4.3)
= (1/2) - 0 + 2 + (25/2 - 20) - (9/2 - 12)
= 1/2 + 2 - 20 + 12 + 25/2 - 9/2
= 1/2 - 6 + 16/2
= 1/2 + 2
= 2 1/2

Maaf sudah bikin lambangnya