Question

Tolong bantu ya kak no. 2 dan 3, please...
Kasih bintang lima deh.

Answer 1

No. 2

-2 1 0 a 0 0 -8
-2 4 -8-2a 16+4a -32-8a
1 -2 4+a -8-2a 16+4a -32-8a = 0

8a = -32
a = -4


maaf ya cuma bisa no. 2

Answer 2

(x + 2) => x = -2
x^5 + ax^3 - 8 'habis dibagi' berarti sisa nya 0
(-2)^5 + a(-2)^3 - 8 = 0
-32 - 8a - 8 = 0
-40 = 8a
a = -40/8 = -5

3) (x - 3) => x = 3
f(3) = 38
x^3 + (k - 4)x^2 + (k + 2)x - 10 = 38
3^3 + (k - 4)(3^2) + (k + 2).3 = 48
27 + 9k - 36 + 3k + 6 = 48
12k = 51
k = 51/12