TOLONG BANTU YA KAK, JANGAN LUPA PAKE CARA, MAKASIH.... Question from @dhistyaardani

Jawab:

$\frac{12}{\sqrt{6} } *\frac{\sqrt{6} }{\sqrt{6} } =\frac{12\sqrt{6} }{(\sqrt{6})(\sqrt{6})} =\frac{12\sqrt{6}}{6} =2\sqrt{6}}\\ \\\\ \frac{1}{\sqrt{3} +\sqrt{2}} *\frac{\sqrt{3} -\sqrt{2}}{\sqrt{3} -\sqrt{2}}=\frac{\sqrt{3} -\sqrt{2}}{(\sqrt{3} +\sqrt{2})(\sqrt{3} -\sqrt{2})}=\sqrt{3} -\sqrt{2} \\ \\ \\ \frac{4}{\sqrt{6} -2} *\frac{\sqrt{6} +2}{\sqrt{6} +2}=\frac{4(\sqrt{6} +2)}{(\sqrt{6} -2)(\sqrt{6} +2)}=\frac{4(\sqrt{6} +2)}{2} = 2\sqrt{6}+4$

$\frac{3}{2\sqrt{2}+\sqrt{5} } *\frac{2\sqrt{2}-\sqrt{5}}{2\sqrt{2}-\sqrt{5}} =\frac{3(2\sqrt{2}-\sqrt{5})}{(2\sqrt{2}+\sqrt{5})(2\sqrt{2}-\sqrt{5})}=\frac{3(2\sqrt{2}-\sqrt{5})}{4*2-5}=\frac{3(2\sqrt{2}-\sqrt{5})}{3}= 2\sqrt{2}-\sqrt{5}$

Semoga membantu ya...

1 votes Thanks 0

BNP999

Penjelasan dengan langkah-langkah:

a). 12/√6 = 12/√6 x √6/√6 = 12√6/6 = (12/6)√6 = 2√6

b). 1/(√3+√2) = 1/(√3+√2) x (√3-√2)/(√3-√2) = 1(√3-√2)/((√3)² - (√2)²) = (√3-√2)/(3-2) = (√3-√2)/1 = √3-√2

c). 4/(√6 - 2)=4/(√6 -2) x (√6+2)/(√6+2) = 4(√6+2)/((√6)²-2²)) = (4√6 + 8)/(6-4) = (8+4√6)/2 = 4+2√6

d). 3/(2√2+√5)=3/(2√2+√5) x (2√2-√5)/(2√2-√5) = 3(2√2-√5)/((2√2)²-(√5)²) = (6√2-3√5)/(8-5)=(6√2-3√5)/3= 2√2-√5

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