Jawaban:
A. 6
B. -16
C. -128
Penjelasan:
[tex]x {}^{2} + 6x - 16 = 0 \\ (x - 8)(x - 2) \\ x1 = 8 \\ x2 = - 2[/tex]
Maka :
[tex]x1 + x2 = 8 + ( - 2) = 6 \\ x1 \times x2 = 8 \times ( - 2) = - 16 \\ x 1 {}^{2} + x2 = 8 {}^{2} \times ( - 2) = - 128[/tex]
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Jawaban:
A. 6
B. -16
C. -128
Penjelasan:
[tex]x {}^{2} + 6x - 16 = 0 \\ (x - 8)(x - 2) \\ x1 = 8 \\ x2 = - 2[/tex]
Maka :
[tex]x1 + x2 = 8 + ( - 2) = 6 \\ x1 \times x2 = 8 \times ( - 2) = - 16 \\ x 1 {}^{2} + x2 = 8 {}^{2} \times ( - 2) = - 128[/tex]
Semoga Membantuu:)