Jawaban:
Lihat gambar
Penjelasan dengan langkah-langkah:
Tegak lurus maka a. b = 0
k(k - 10 ) + (-k) (2) + 4(1) = 0
k² - 10k - 2k + 4 = 0
k² - 12k + 4 = 0
[tex] {k}^{2} - 12k + 4 = 0 \\ k = \frac{ 12 \: \pm \: \sqrt{ {( - 12) }^{2} - 4(1)(4) } }{2(1)} \\ = \frac{12 \pm \: \sqrt{144 - 16} }{2} \\ = \frac{12 \pm \sqrt{128} }{2} \\ = 6 \pm \: 4 \sqrt{2} [/tex]
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Jawaban:
Lihat gambar
Penjelasan dengan langkah-langkah:
Tegak lurus maka a. b = 0
k(k - 10 ) + (-k) (2) + 4(1) = 0
k² - 10k - 2k + 4 = 0
k² - 12k + 4 = 0
[tex] {k}^{2} - 12k + 4 = 0 \\ k = \frac{ 12 \: \pm \: \sqrt{ {( - 12) }^{2} - 4(1)(4) } }{2(1)} \\ = \frac{12 \pm \: \sqrt{144 - 16} }{2} \\ = \frac{12 \pm \sqrt{128} }{2} \\ = 6 \pm \: 4 \sqrt{2} [/tex]