Question

tolong bantu kerjakan
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Answer 1

1. ∠x = 155°.
   ∠y = 70°.
2. Nilai x = 10°.
   ∠AOE = 20°.
   ∠COD = 70°
   ∠AOB = 160°.

 

Penjelasan dengan langkah-langkah

Nomor 1

∠a = 95°, ∠b = 70°.
⇔ Pelurus ∠a = 180° – 95° = 85°

Maka:
∠x = 180° – (180° – pelurus ∠a – ∠b)
⇔ ∠x = pelurus ∠a + ∠b
⇔ ∠x = 85° + 70° = 155°

Periksa:
Pelurus ∠x = 180° – 155° = 25°
Pelurus ∠x + pelurus ∠a + ∠b = 180°
⇔ 25° + 85° + 70° = 180°
⇔ 180° = 180° (benar).

Untuk ∠y, besar ∠y jelas sama dengan ∠b, yaitu 70°.
_________

Nomor 2

Jumlah derajat 1 putaran = 360°.
⇔ 2 × ∠DOE + 2·(∠AOE + ∠BOC) = 360°
⇔ 2 × 90° + 2·(2x + 7x) = 360°
⇔ 180° + 18x = 360°
⇔ 18x = 180°
⇔ x = 10°

• ∠AOE = 2x = 20°.
• ∠COD = 7x = 70°.
• ∠AOB = 90° + 7x = 90° + 70° = 160°.

Answer 2

Jawaban:

1. x = 155°

y = 70°

..

2. x = 10°

AOE = 20°

COD = 70°

AOB = 160°

Penjelasan dengan langkah-langkah:

sudut berpelurus = 180°

sudut bertolak belakang besarnya sama

..

1.

a. x = 180 - d

x = 180 - (180 - b - c)

x = 180 - (180 - b - (180 - a))

x = 180 - (180 - 70 - (180 - 95))

x = 180 - (180 - 70 - 85)

x = 180 - 25

x = 155°

..

y = b (sudut bertolak belakang)

y = 70°

..

2.

AOE, EOD, dan DOC = berpelurus

AOE + EOD + DOC = 180

2x + 90 + 7x = 180

90 + 9x = 180

9x = 90

x = 10°

..

AOE = 2x

AOE = 2(10)

AOE = 20°

..

COD = 7x

COD = 7(10)

COD = 70°

..

AOB = EOC

AOB = EOD + DOC

AOB = 90 + 70

AOB = 160°

[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}[/tex]