Bagian A
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Bagian B
Bagian C
Penjelasan dengan langkah-langkah:
a). 1/(2√3) = 1/(2√3) x (2√3)/(2√3) = (2√3)/(2²√3²)= (2√3)/(12)= 1/6√3
b). 6/(5-2√3)= 6/(5-2√3) x (5+2√3)/(5+2√3)= 6(5+2√3)/(5² - (2√3)² = 6(5+2√3)/(25-12)= 6(5+2√3)/(13)= (30+12√3)/13
c). (2√3 + √6)/(2√3 - √6)= (2√3+√6)/(2√3-√6) x (2√3 +√6)/(2√3+√6)= 2√3(2√3 + √6)+√6(2√3+√6)/(2√3)² - (√6)² = (4√9 + 2√18 + 2√18 + √36 = (4(3)+4√18+6)/(12-6)= (12+6+4√(9x2))/(6) = (18+4(3)√2))/6= (18+12√2)/6 = (18/6 + 12/6√2) = (3 + 2√2)
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Bagian A
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Bagian B
ㅤㅤㅤㅤㅤㅤ
Bagian C
Penjelasan dengan langkah-langkah:
a). 1/(2√3) = 1/(2√3) x (2√3)/(2√3) = (2√3)/(2²√3²)= (2√3)/(12)= 1/6√3
b). 6/(5-2√3)= 6/(5-2√3) x (5+2√3)/(5+2√3)= 6(5+2√3)/(5² - (2√3)² = 6(5+2√3)/(25-12)= 6(5+2√3)/(13)= (30+12√3)/13
c). (2√3 + √6)/(2√3 - √6)= (2√3+√6)/(2√3-√6) x (2√3 +√6)/(2√3+√6)= 2√3(2√3 + √6)+√6(2√3+√6)/(2√3)² - (√6)² = (4√9 + 2√18 + 2√18 + √36 = (4(3)+4√18+6)/(12-6)= (12+6+4√(9x2))/(6) = (18+4(3)√2))/6= (18+12√2)/6 = (18/6 + 12/6√2) = (3 + 2√2)