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H⁺ = n M = 2 x 0,3 = 0,6 = 6 x 10⁻¹ M
pH = -log H⁺ = -log 6 x 10⁻¹ = 1 - log 6
pH Ca(OH)₂
OH⁻ = n M = 2 x 0,15 = 0,3 = 3 x 10⁻¹ M
pOH = -log OH⁻ = -log 3 x 10⁻¹ = 1 - log 3
pH = 14 - (1-log 3) = 13 + log 3
b. H₂CO₃ + Ca(OH)₂ => CaCO₃ + 2H₂O
M 60 30 - -
R 30 30 30 60
S 30 - 30 60
Terbentuk larutan penyagga
c. H⁺ = ka mol asam / mol garam
= 2 x 10⁻⁴ 30/30
= 2 x 10⁻⁴
pH = -log H⁺ = -log 2 x 10⁻⁴ = 4 - log 2
d. gak tau maksud soalnya