Question

tolong bantu kakak-kakak ​

Answer 1

Penjelasan dengan langkah-langkah:

1. ac = 10 cm

sudut a = 30°

panjang ab

cos a = ab/ac

cos 30° = ab/10

√3/2 = ab/10

10√3 = 2ab

ab = 5√3 cm

panjang bc

sin a = bc/ac

sin 30° = bc/10

1/2 = bc/10

10 = 2bc

bc = 5 cm

atau gunakan perbandingan segitiga istimewa 90 : 60 : 30 = 2 : √3 : 1, dimana ac : ab : bc = 2 : √3 : 1

2. ab = 12√2

sudut c = 45°

panjang bc

tan 45° = bc/ab

1 = bc/12√2

bc = 12√2

panjang ac

sin 45° = ab/ac

√2/2 = 12√2/ac

ac√2 = 24√2

ac = 24 cm

perbandingan segitiga istimewa 45° : 45° : 90° = 1 : 1 : √2

3. pr = 18 cm

sudut r = 60°

panjang qr

cos 60° = pq/pr

1/2 = qr/18

2qr = 18

qr = 9 cm

panjang pq

sin 60° = pq/pr

√3/2 = pq/18

18√3 = 2pq

pq = 9√3 cm