Jawaban:
1. 2.304 cm²
2. 1.256 cm²
Penjelasan dengan langkah-langkah:
tinggi segitiga = √(32÷2)² + 12² = √256+144 = √400 = 20 cm
1.Lp Limas = luas alas + luas sisi tegak
= (s×s) + (4×1/2×alas×tinggi)
= (32×32) + (4×1/2×32×20)
= 1.024 + (4/2×640)
= 1.024 + (12.560/2)
= 1.024 + 1.280
= 2.304 cm²
2.Lp bola = 4×π×r²
= 4×3,14×10×10
= 4×314
=1.256 cm²
maaf kalau salah
semoga membantu
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Jawaban:
1. 2.304 cm²
2. 1.256 cm²
Penjelasan dengan langkah-langkah:
tinggi segitiga = √(32÷2)² + 12² = √256+144 = √400 = 20 cm
1.Lp Limas = luas alas + luas sisi tegak
= (s×s) + (4×1/2×alas×tinggi)
= (32×32) + (4×1/2×32×20)
= 1.024 + (4/2×640)
= 1.024 + (12.560/2)
= 1.024 + 1.280
= 2.304 cm²
2.Lp bola = 4×π×r²
= 4×3,14×10×10
= 4×314
=1.256 cm²
maaf kalau salah
semoga membantu