Jawaban:
1.) 1/3 × r² × t
1/3 × 8² × 15
1/3 × 64 × 15
1/3 × 960
= 320 π
taunya nomor 1 aja sorry
PEMBAHASAN
Bangun Ruang
Kerucut
No. 14
Volume kerucut
= 1/3 × luas alas × tinggi
= 1/3 × πr² × t
= 1/3 × π × 8² × 15
= π × 64 × 5
= 320π cm³
No. 15
garis pelukis kerucut = s
= √(r² + t²)
= √(8² + 15²)
= √(64 + 225)
= √289
= 17 cm
Luas selimut kerucut
= πrs
= π × 8 × 17
= 136π cm²
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Jawaban:
1.) 1/3 × r² × t
1/3 × 8² × 15
1/3 × 64 × 15
1/3 × 960
= 320 π
taunya nomor 1 aja sorry
Verified answer
PEMBAHASAN
Bangun Ruang
Kerucut
No. 14
Volume kerucut
= 1/3 × luas alas × tinggi
= 1/3 × πr² × t
= 1/3 × π × 8² × 15
= π × 64 × 5
= 320π cm³
No. 15
garis pelukis kerucut = s
= √(r² + t²)
= √(8² + 15²)
= √(64 + 225)
= √289
= 17 cm
Luas selimut kerucut
= πrs
= π × 8 × 17
= 136π cm²