Jawaban:
mis: u = -6x + 1
[tex] \frac{du}{dx} = - 6[/tex]
[tex]dx = - \frac{1}{6} du[/tex]
∫-sin(-6x+1) dx
= -∫sin(-6x+1) dx
= -∫sin u × -⅙ du
= ⅙∫sin u du
= ⅙(-cos u) + c
= -⅙cos u + c
= -⅙cos(-6x+1) + c
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawaban:
mis: u = -6x + 1
[tex] \frac{du}{dx} = - 6[/tex]
[tex]dx = - \frac{1}{6} du[/tex]
∫-sin(-6x+1) dx
= -∫sin(-6x+1) dx
= -∫sin u × -⅙ du
= ⅙∫sin u du
= ⅙(-cos u) + c
= -⅙cos u + c
= -⅙cos(-6x+1) + c