Question

Tolong bantu jawaban dan caranya ya.Terima kasih sebelumnya

Answer 1

Jawaban:

(x - p)² + (y + q)² = a

pusat = (p, - q)

r = √a

Answer 2

•

x² - 3x + 2 = 0

(x - 1)(x - 2) = 0

x = 1 atau x = 2

p(x) = x³ + ax² - 4x + b

p(1) = 9x - 5

1³ + a.1² - 4.1 + b = 9.1 - 5

a + b = 4 ... (1)

p(2) = 9x - 5

4a + b = 13 ... (2)

Eliminasi substitusi (1) dan (2)

a = 3 dan b = 1

a - b = 2 ✔

••

(x - p)² + (y + q)² = a

Pusat = (p,-q)

r = √a

•••

x - 2 = 0

x = 2

f(x) = 2x³ + ax² + bx - 2

f(2) = 0

4a + 2b = -14

2a + b = -7 ... (1)

x + 3 = 0

x = -3

f(-3) = -50

9a - 3b = 6

3a - b = 2 ... (2)

Eliminasi substitusi (1) dan (2)

a = -1 dan b = -5

a + b = -6 ✔