Jawab:
Penjelasan dengan langkah-langkah:
log (2x + y) = 1
2x + y = 10¹
2x + y = 10
y = 10 - 2x
^ artinya pangkat
2^y = (2^(2x))/4
2^y = 2^(2x) . 2⁻²
2^y = 2^(2x - 2)
y = 2x - 2
2x - 2 = 10 - 2x
2x + 2x = 10 + 2
4x = 12
x = 12 : 4
x = 3
y = 2 . 3 - 2
y = 4
x . y
= 3 . 4
= 12
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Jawab:
Penjelasan dengan langkah-langkah:
log (2x + y) = 1
2x + y = 10¹
2x + y = 10
y = 10 - 2x
^ artinya pangkat
2^y = (2^(2x))/4
2^y = 2^(2x) . 2⁻²
2^y = 2^(2x - 2)
y = 2x - 2
2x - 2 = 10 - 2x
2x + 2x = 10 + 2
4x = 12
x = 12 : 4
x = 3
y = 2x - 2
y = 2 . 3 - 2
y = 4
x . y
= 3 . 4
= 12