Penjelasan:
1. a. Mr CH4 = 16
Rumus Volume pd keadaan STP:
V = n x 22,4
8 = n x 22,4
n = 0,36 mol
m = n x Mr CH4
m = 0,36 x 44
m = 15,84 gram
b. Jumlah molekul = n x 6,02 x 10^23
=> 0,36 x 6,02 x10^23
=> 2,17 x 10^23 molekul
c. Jumlah atom pada CH4 = ( 1x atom C ) + ( 4x atom H ) jadi total 5 atom
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Penjelasan:
1. a. Mr CH4 = 16
Rumus Volume pd keadaan STP:
V = n x 22,4
8 = n x 22,4
n = 0,36 mol
m = n x Mr CH4
m = 0,36 x 44
m = 15,84 gram
b. Jumlah molekul = n x 6,02 x 10^23
=> 0,36 x 6,02 x10^23
=> 2,17 x 10^23 molekul
c. Jumlah atom pada CH4 = ( 1x atom C ) + ( 4x atom H ) jadi total 5 atom