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Panjang 2 batang : Lo = 20+20 = 40 m
T1 = 20°C
T2 = 50°C
ΔT = T2-T1 = 50-20 = 30°C
α = 0,000012/°C
a. ΔL = Lo.α.ΔT = 40.0,000012.30 = 0,0144 m
b. 2ΔL = 0,0144.2 = 0,0288 m